(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)
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(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)求解：解析：解答5.原式=x+2xy+2y-1. y-l x2-1 2y2+xy+y+x-1x-1 y-1x2+2xy+2y-1__y+1x+1 2y2+xy+y+x-1 _x2+2xy+y²-y2+2y-1.x+1y+12y2-2+xy+y+x+1(x+y)²-(y-1)².x+1y+12(y+1)(y-1)+(x+1)(y+1)(x+y+y-1)(x+y-y+1).x+1y+1(y+1)(2y-2+x+1)=(x+2y-1)·x+2y-1=1。
您好(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)求解：解析：解答5.原式=x+2xy+2y-1. y-l x2-1 2y2+xy+y+x-1x-1 y-1x2+2xy+2y-1__y+1x+1 2y2+xy+y+x-1 _x2+2xy+y²-y2+2y-1.x+1y+12y2-2+xy+y+x+1(x+y)²-(y-1)².x+1y+12(y+1)(y-1)+(x+1)(y+1)(x+y+y-1)(x+y-y+1).x+1y+1(y+1)(2y-2+x+1)=(x+2y-1)·x+2y-1=1。
咨询记录 · 回答于2022-12-15
(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)
亲~亲您好(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)求解：解析：解答绝历5.原式并桥搜=x+2xy+2y-1. y-l x2-1 2y2+xy+y+x-1x-1 y-1x2+2xy+2y-1__y+1x+1 2y2+xy+y+x-1 _x2+2xy+y²-y2+2y-1.x+1y+12y2-2+xy+y+x+1(x+y)²消消-(y-1)².x+1y+12(y+1)(y-1)+(x+1)(y+1)(x+y+y-1)(x+y-y+1).x+1y+1(y+1)(2y-2+x+1)=(x+2y-1)·x+2y-1=1。
您好(x⁻¹+y⁻¹)÷(x⁻²-y⁻²)求解：解析：解答绝历5.原式并桥搜=x+2xy+2y-1. y-l x2-1 2y2+xy+y+x-1x-1 y-1x2+2xy+2y-1__y+1x+1 2y2+xy+y+x-1 _x2+2xy+y²-y2+2y-1.x+1y+12y2-2+xy+y+x+1(x+y)²消消-(y-1)².x+1y+12(y+1)(y-1)+(x+1)(y+1)(x+y+y-1)(x+y-y+1).x+1y+1(y+1)(2y-2+x+1)=(x+2y-1)·x+2y-1=1。
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