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已知(x+y-2)²+Ιz-3Ι=0,求代数式(x+y)+³-3(x+y)+z²-z³的值
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你好,根据(x+y-2)²+Ιz-3Ι=0,所以x+y-2=0,z-3=0,所以x+y=2,z=3
咨询记录 · 回答于2022-08-18
已知(x+y-2)²+Ιz-3Ι=0,求代数式(x+y)+³-3(x+y)+z²-z³的值
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怎么还没出来呢
你好,根据(x+y-2)²+Ιz-3Ι=0,所以x+y-2=0,z-3=0,所以x+y=2,z=3
然后代入后面的代数式得到,2^3-3x2+3^2-3^3=-1
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你好,还有其他问题吗
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不好意思,应该等于8-6+9-27=—16
少打了一个6
正确答案-16
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