Question

初二因式分解题求解~~

1+10t+25t2

m2-14m+49

y2+y+1/4

(m+n)2-4m(m+n)+4m2

25a2-80a+64

a2+2a(b+c)+(b+c)2

(p-4)(p+1)+3p

(注意:x2指的是x的平方,以此类推~)

谢谢大家帮忙拉!今晚要~速度~谢谢~

Answer 1

(5t+1)2
(m-7)2
(y+1/2)2
(m+n-2m)2
(5a-8)2
(a+b+c)2
(p+2)(P-2)
楼上好几个错的啊，羞死人了。

Answer 2

1+10t+25t2 ＝（1+5t)^2

m2-14m+49 ＝（m-7)^2

y2+y+1/4 ＝（y+1/2)^2

(m+n)2-4m(m+n)+4m2 ＝（m+n-2m)^2＝（n-m)^2

25a2-80a+64 ＝（5a-8)^2

a2+2a(b+c)+(b+c)2 ＝（a+(b+c))^2=(a+b+c)^2

(p-4)(p+1)+3p ＝p^2-3p-4+3p=p^2-4=(p+2)(p-2)

Answer 3

1. （5t+1)^2
2. （m-7)^2
3. (y+0.5)^2
4. (m+n-2m)^2
5. (5a-8)^2
6. (a+b+c)^2
7. (p+2)(p-2)

Answer 4

(5t+1)2
(m-7)2
(y+1/2)2
(n-m)2
(5a2-8)
(a+b+c)2
(p+2)(p-2)
(2也指的是x的平方)