Question

c语言 s=2/1!+4/3!+6/5!+…2n/(2n-1)!

Answer 1

问：c语言 s=2/1!+4/3!+6/5!+…2n/(2n-1)!

答：# 题目：c语言 s=2/1!+4/3!+6/5!+…2n/(2n-1)! 亲，您好！ 答：S = 1/2 + 3/4 + 5/8 + 7/16 + … + (2n-1)/2^n --------------------------------① S/2 = 1/4 + 3/8 + 5/16 + … + (2n-3)/2^n + (2n-1)/2^(n+1)-------------② ① - ② 得： S/2 = 1/2 + 1/2 + 1/2^2 + … + 1/2^(n-1) - (2n-1)/2^(n+1) = 3/2 - 1/2^(n-1) - (2n-1)/2^(n+1) 所以：S = 3 - (2n+3)/2^n 希望能帮助的到您！