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在三角形abc中,角BAC等于15°,AB等于3*根号2,AC等于7线段BC绕点C逆时针旋转60°得到线段CD,连接AD,求AD长
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亲亲,非常荣幸为您解答![](https://s.bdstatic.com/common/openjs/emoticon/img/face_02.png)
首先要在三角形ABC中求出BC的长度。根据正弦定理有:sin15°/BC = sin60°/(7BC),化简可得:BC = 3√6
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咨询记录 · 回答于2023-04-21
在三角形abc中,角BAC等于15°,AB等于3*根号2,AC等于7线段BC绕点C逆时针旋转60°得到线段CD,连接AD,求AD长
等着呢
亲亲,非常荣幸为您解答![](https://s.bdstatic.com/common/openjs/emoticon/img/face_02.png)
首先要在三角形ABC中求出BC的长度。根据正弦定理有:sin15°/BC = sin60°/(7BC),化简可得:BC = 3√6
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_02.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_02.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_02.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_207.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_246.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_246.png)
![](https://s.bdstatic.com/common/openjs/emoticon/img/face_03.png)
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