Question

设 lim_(x)((x^2+1)/(x+1)-ax+b)=3,求a,b值

Answer 1

问：设 lim_(x)((x^2+1)/(x+1)-ax+b)=3,求a,b值

答：当x趋于正无穷时，lim_(x)((x^2+1)/(x+1)-ax+b)=3即可得出a=1,b=2。