Log以2为底3整体的平方怎么算

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翰墨小七老师

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摘要抱歉，我可能算错了，我重新考虑一下。

log2(3) = log10(3) / log10(2)

所以 10^(log10(3) / log10(2)) = 3

[(log10(3) / log10(2))]2 = (log10(3)^2) / (log10(2)^2)

[log10(3)^2] / [log10(2)^2] = log10(3^2) / log10(2^2)

log10(3^2) / log10(2^2) = (2 * log10(3)) / (2 * log10(2))

已知 log10(3) / log10(2) = 1,

所以：(2 * log10(3)) / (2 * log10(2)) = 2 * (log10(3)) / (log10(2)) = 2 * 1 = 2

所以，log2(3)的平方等于2。

咨询记录 · 回答于2024-01-05

Log以2为底3整体的平方怎么算

亲，您好！非常高兴为您进行解答哦~

log以2为底的3的对数平方等于36。

怎么算

抱歉，我可能算错了，我重新考虑一下。 log2(3) = log10(3) / log10(2) 所以10^(log10(3) / log10(2)) = 3 [(log10(3) / log10(2))]2 = (log10(3)^2) / (log10(2)^2) [log10(3)^2] / [log10(2)^2] = log10(3^2) / log10(2^2) log10(3^2) / log10(2^2) = (2 * log10(3)) / (2 * log10(2)) 已知log10(3) / log10(2) = 1, 所以：(2 * log10(3)) / (2 * log10(2)) = 2 * (log10(3)) / (log10(2)) = 2 * 1 = 2 所以，log2(3)的平方等于2。

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