an+1=【nan-(2n+1)】/n+1 求an
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您好,an+1=【nan-(2n+1)】/n+1 解方程两边同时乘以n+1得n*an+an+n+1=nan-2n-1 an=-3n-2
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an+1=【nan-(2n+1)】/n+1 求an
您好,an+1=【nan-(2n+1)】/n+1 解方程两边同时乘以n+1得n*an+an+n+1=nan-2n-1 an=-3n-2
明白了吗?亲
检验,把an=-3n-2代入方程an+1=【nan-(2n+1)】/n+1 左边得-3n-2+1=-3n-1把an=-3n-2代入方程an+1=【nan-(2n+1)】/n+1 右边得(-3n^2-2n-2n-1)/ (n-1)=(-3n^2-4n-1)/( n+1)=-(3n+1)( n+1)/( n+1)=-3n-1右边=左边∴an=-3n-2是方程an+1=【nan-(2n+1)】/n+1 的解
明白了吗?亲
an+1的n+1是右下标
所以应该是?
您好an+1=【nan-(2n+1)】/n+1 求an中分母n+1还是n