Question

利用malab求解二阶微分方程 (dy)/(dx^2)=2+ay+1/3bx？

Answer 1

问：利用malab求解二阶微分方程 (dy)/(dx^2)=2+ay+1/3bx？

答：利用malab求解二阶微分方程 (dy)/(dx^2)=2+ay+1/3bx？解答：∫dy/(2y+1) =∫ dx(1/2)ln|2y+1| = x+C'ln|2y+1| = 2x+2C'2y+1 =Ce^(2x)y= [-1+Ce^(2x)]/2y(0) =33= [-1+C]/2C=7iey= [-1+7e^(2x)]/2