Question

SUM(IF(1>2,"1",2"),3)+22 /2-(2+2)&"1"

Answer 1

问：SUM(IF(1>2,"1",2"),3)+22 /2-(2+2)&"1"

答：亲很高兴回答您的问题 SUM(IF(1>2,"1",2"),3)+22 /2-(2+2)&"1"给定的表达式在语法上无效。表达式中存在一些错误，需要先进行更正，然后才能对其进行求值。IF语句未正确关闭。第二个双引号字符放错地方了。除法运算符（/）的优先级高于加法（+）和减法（-）运算符。因此，将首先对表达式（22/2）进行评估。串联运算符（&）的优先级低于算术运算符。因此，将首先对表达式（2+2）进行求值。要更正这些错误，可以按如下方式编写表达式：=总和（如果（1>2，“1”，2），3）+（22/2）-（2+2）&“1”现在，让我们一步一步地评估这个表达式：IF（1>2，“1”，2）的求值结果为2，因为1不大于2。SUM（2,3）的计算结果为5。（22/2）评估为11。（2+2）计算为4。“-4”和“1”的串联计算结果为“-41”。最后，从5中减去11得到-6。因此，表达式的最终结果是-6。

答：The given expression is not syntactically valid. There are some errors in the expression which need to be corrected before it can be evaluated.The IF statement is not properly closed. The second double-quote character is misplaced.The division operator (/) has higher precedence than addition (+) and subtraction (-) operators. Therefore, the expression (22 / 2) will be evaluated first.The concatenation operator (&) has lower precedence than arithmetic operators. Therefore, the expression (2 + 2) will be evaluated first.To correct these errors, the expression can be written as follows:=SUM(IF(1>2,"1",2),3)+(22/2)-(2+2)&"1"Now, let's evaluate this expression step by step:IF(1>2,"1",2) evaluates to 2, because 1 is not greater than 2.SUM(2,3) evaluates to 5.(22/2) evaluates to 11.(2+2) evaluates to 4.The concatenation of "-4" and "1" evaluates to "-41".Finally, the subtraction of 11 from 5 evaluates to -6.Therefore, the final result of the expression is -6.

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