英文数学题解答两道
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你好,第二题答案:The probabilities for each branch are:P(RR) = (2/6) * (1/5) = 1/15P(RG) = (2/6) * (4/5) = 8/30 = 4/15P(GR) = (4/6) * (2/5) = 8/30 = 4/15P(GG) = (4/6) * (3/5) = 2/3a) The probability that the first marble drawn is red and the second marble is green is P(RG) = 4/15.b) The probability that two marbles of the same color are drawn is P(RR) + P(GG) = 1/15 + 2/3 = 29/45.c) The probability that at least one red marble is drawn is 1 - P(GG) = 1 - 2/3 = 1/3.
咨询记录 · 回答于2023-05-06
英文数学题解答两道
你好,第二题答案:The probabilities for each branch are:P(RR) = (2/6) * (1/5) = 1/15P(RG) = (2/6) * (4/5) = 8/30 = 4/15P(GR) = (4/6) * (2/5) = 8/30 = 4/15P(GG) = (4/6) * (3/5) = 2/3a) The probability that the first marble drawn is red and the second marble is green is P(RG) = 4/15.b) The probability that two marbles of the same color are drawn is P(RR) + P(GG) = 1/15 + 2/3 = 29/45.c) The probability that at least one red marble is drawn is 1 - P(GG) = 1 - 2/3 = 1/3.
第一题A问题:A 0.52 0.12 0.25A' 0.12 0.48 0.25 0.52 0.48 0.25
第一题B问题答案:i. Pr(A) is the sum of probabilities for all the squares where A=1, which is: Pr(A) = 0.12 + 1 + 1 = 2.12ii. Pr(ANB) is the probability of the squares where both A=1 and B=1, which is: Pr(ANB) = 1iv. Pr(A UB) is the sum of probabilities for all the squares where either A=1 or B=1 or both, which is: Pr(A UB) = 0.12 + 1 + 0.25 + 1 + 1 + 1 = 4.37