Question

5已知:(x+m)/(4-x^2)+m/(x-2)=1.无解求m的值

Answer 1

问：5已知:(x+m)/(4-x^2)+m/(x-2)=1.无解求m的值

答：亲，很高兴为您解答！5已知:(x+m)/(4-x^2)+m/(x-2)=1.无解求m的值的详细解答：这道题可以通过将左边的式子化简，然后将其与右边的式子进行比较，来求解m的值。首先，将左边的式子化简：(x+m)/(4-x^2)+m/(x-2)=1= (x+m)(x-2)/(4-x^2)(x-2) + m/(x-2)= (x^2+xm-2x+2m)/(4-x^2)(x-2) + m/(x-2)= (x^2+xm-2x+2m+m(4-x^2))/(4-x^2)(x-2)= (x^2+xm-2x+6m)/(4-x^2)(x-2)将左边的式子与右边的式子进行比较，可以得出：x^2+xm-2x+6m=4-x^2x^2+xm-6m=4xm-6m=4-x^2m(x-6)=4-x^2m= (4-x^2)/(x-6)由于m是一个常数，所以可以得出：m= (4-x^2)/(x-6)，其中x为任意实数。