24.已知A=x+y,B=x2-y2C=x2-2xy+y2.(1

1个回答

hom喵喵

专业答主服务有保障

关注

展开全部

摘要亲你好，非常高兴为你解答，解析](1)根据题意列出算式,再去括号、合并同类项可得;(2)由2A﹣3B+C=0可得C=3B﹣2A=3(x2+2xy+y2)﹣2(x2﹣2xy+y2),再去括号、合并同类项可得.[详解]解:(1)A+B=(x2﹣2xy+y2)+(x2+2xy+y2)=x2﹣2xy+y2+x2+2xy+y2=2x2+2y2;(2)因为2A﹣3B+C=0,所以C=3B﹣2A=3(x2+2xy+y2)﹣2(x2﹣2xy+y2)=3x2+6xy+3y2﹣2x2+4xy﹣2y2=x2+10xy+y2

咨询记录 · 回答于2022-12-28

24.已知A=x+y,B=x2-y2C=x2-2xy+y2.(1

亲你好，非常高兴为你解答，解析](1)根据题意列出算式,再去括号、合并同类项可得;(2)由2A﹣3B+C=0可得C=3B﹣2A=3(x2+2xy+y2)﹣2(x2﹣2xy+y2),再去括号、合并同类项可得.[详解]解:(1)A+B=(x2﹣2xy+y2)+(x2+2xy+y2)=x2﹣2xy+y2+x2+2xy+y2=2x2+2y2;(2)因为2A﹣3B+C=0,所以C=3B﹣2A=3(x2+2xy+y2)﹣2(x2﹣2xy+y2)=3x2+6xy+3y2﹣2x2+4xy﹣2y2=x2+10xy+y2

求解

求助

已赞过

评论收起