8x1x4+2x3x4+2x2x3+8x2x4配方法化为标准型
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8x1x4+2x3x4+2x2x3+8x2x4配方法化为标准型 为：
A=
0 0 0 4
0 0 1 4
0 1 0 1
4 4 1 0
(A;E)=
0 0 0 4
0 0 1 4
0 1 0 1
4 4 1 0
1 0 0 0
0 1 0 0
0 0 1 0
0 0 0 1
r4+r3(作相应的列变换c4+c3)
0 0 0 4
0 0 1 5
0 1 0 1
4 5 1 2
1 0 0 0
0 1 0 0
0 0 1 1
0 0 0 1
r2-r1-r3,r1-2r4,r3-(1/2)r4
-8 0 -2 0
0 -2 1 0
-2 1 -1/2 0
0 0 0 2
1 -1 0 0
0 1 0 0
-2 -1 1/2 1
-2 0 -1/2 1
r3-(1/4)r1
-8 0 0 0
0 -2 1 0
0 1 0 0
0 0 0 2
1 -1 -1/4 0
0 1 0 0
-2 -1 1 1
-2 0 0 1
r3+(1/2)r2
-8 0 0 0
0 -2 0 0
0 0 1/2 0
0 0 0 2
1 -1 -3/4 0
0 1 1/2 0
-2 -1 1/2 1
-2 0 0 1
令 C =
1 -1 -3/4 0
0 1 1/2 0
-2 -1 1/2 1
-2 0 0 1
则 C^TAC =
-8 0 0 0
0 -2 0 0
0 0 1/2 0
0 0 0 2
令 X=CY 则 f = -8y1^2 -2y2^2 + 1/2y3^2 + 2y4^2.
咨询记录 · 回答于2022-03-02
8x1x4+2x3x4+2x2x3+8x2x4配方法化为标准型
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8x1x4+2x3x4+2x2x3+8x2x4配方法化为标准型 为：A=0 0 0 40 0 1 40 1 0 14 4 1 0(A;E)=0 0 0 40 0 1 40 1 0 14 4 1 01 0 0 00 1 0 00 0 1 00 0 0 1r4+r3(作相应的列变换c4+c3)0 0 0 40 0 1 50 1 0 14 5 1 21 0 0 00 1 0 00 0 1 10 0 0 1r2-r1-r3,r1-2r4,r3-(1/2)r4-8 0 -2 00 -2 1 0-2 1 -1/2 00 0 0 21 -1 0 00 1 0 0-2 -1 1/2 1-2 0 -1/2 1r3-(1/4)r1-8 0 0 00 -2 1 00 1 0 00 0 0 21 -1 -1/4 00 1 0 0-2 -1 1 1-2 0 0 1r3+(1/2)r2-8 0 0 00 -2 0 00 0 1/2 00 0 0 21 -1 -3/4 00 1 1/2 0-2 -1 1/2 1-2 0 0 1令 C =1 -1 -3/4 00 1 1/2 0-2 -1 1/2 1-2 0 0 1则 C^TAC =-8 0 0 00 -2 0 00 0 1/2 00 0 0 2令 X=CY 则 f = -8y1^2 -2y2^2 + 1/2y3^2 + 2y4^2.
以上是根据您的问题做的解答，希望能够帮到您，谢谢
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