Question

5求与两定点A(3,4)B(2,1)距高相等的动点轨迹方程

Answer 1

问：5求与两定点A(3,4)B(2,1)距高相等的动点轨迹方程

答：设与两定点A，B距离相等的点C坐标为（x,y）AC^2=(x-2)^2+(y+3)^2BC^2=(x-1)^2+(y-2)^2AC^2=BC^2所以有(x-2)^2+(y+3)^2=(x-1)^2+(y-2)^2化简后可得：-x+5y+4=0即为所求的轨迹方程。