Question

√1-x² 求导怎么求

Answer 1

问：√1-x² 求导怎么求

答：您好，答案和步骤如下。y=√（1-x²)u=1-x²,y=√u=u^(1/2)复合函数求导,外到乘以内导即 y'=(√u)' *u'=1/2*u^(-1/2) *u'=1/2*1/√(1-x²)*(1-x²)'=1/[2√(1-x²)]*(-2x)=-x/√(1-x²)

问：y=1/√1-x² 求导

答：解：本题属于复合函数求导！f(x)=1/√(1-x²)f'(x)= [-1/(1-x²)]*[√(1-x²)]'=[-1/(1-x²)] * [(1/2)/√(1-x²)] *[1-x²]'=[-1/(1-x²)] * [(1/2)/√(1-x²)] * -(2x)=x [(1-x²)^(-3/2)]