Question

C语言：若a的值小于100，请将以下选择结构改写成由switch语句构成的选择结构：

若a的值小于100，请将以下选择结构改写成由switch语句构成的选择结构：
if (a<30) m=1;
else if (a<40) m=2;
else if (a<50) m=3;
else if (a<60) m=4;else m=5;

Answer 1

楼主:
非要改的话还得加一个限制条件a大于0,
这样的话这这样做:

int a;
switch(a/10)
{
case 5:m = 4;break;
case 4:m = 3;break;
case 3:m = 2;break;
case 2:m = 1;break;
case 1:m = 1;break;
case 0;m = 1;break;
default:m = 5;
}

Answer 2

判断他的十位数即a/10，
switch( a/10)
{
case 5:m = 4;break;
case 4:m = 3;break;
case 3:m = 2;break;
case 2: //if(a<30)的情况
case 1:
case 0;m = 1;break;
default:m = 5;
}

Answer 3

#include <stdio.h>
#include <string.h>
case 49:
int main(void)
{
int m = 0;
int a = 0;
printf("Input Number a:\n");
scanf("%d" , &a);
switch( a )
{
case 59:
case 58:
case 57:
case 56:
case 55:
case 54:
case 53:
case 52:
case 51:
case 50:
m++;
case 49:
case 48:
case 47:
case 46:
case 45:
case 44:
case 43:
case 42:
case 41:
case 40:
m++;
break;
default:
m = 5;
}
printf("[%d]" , m);
return( 0 );
}

思路就是这样，你自己再添加case语句

Answer 4

switch( a/10)