Question

tana=√2-1 a是多少

Answer 1

问：tana=√2-1 a是多少

答：x = arctan (√2+1)tan2x = 2tanx/(1-tan^2x) = 2 (√2+1)/[1- (√2+1)^2] = -1Therefore, 2x = 3π/4x = 3π/8

答：等一下给你写√2-1的度数

答：x = arctan (√2-1)tan2x = 2tanx/(1+tan^2x) = 2 (√2-1)/[1+ (√2-1)^2]

答：等一下给你一个一个计算

答：x = arctan (√2-1)tan2x = 2tanx/(1-tan^2x) = 2 (√2-1)/[1+-(√2-1)^2]= 2 (√2-1)/[1-2+2√2-1]=√2-1/√2+1=2-2√2+1=3-2√2

答：斜率为√2-1，夹角为arctan(√2-1)。

答：√2-1=1.41-1=0.41

答：arctan0.41等于22度17分37.1秒