Question

az az)设 z=u^2lnv ,u=2xy, v=x^2-y^2 ,求 (z)/(x) (z)/(y)

Answer 1

问：az az)设 z=u^2lnv ,u=2xy, v=x^2-y^2 ,求 (z)/(x) (z)/(y)

问：是打勾的第二题

答：亲，很高兴为您解答。为您查询到的解析如下: u=xy∂u/∂x = y∂u/∂y = xv=x^2+y^2∂v/∂x = 2x∂v/∂y = 2yz=u^2.lnv∂z/∂x=u^2. (1/v).∂v/∂x + (lnv). ( 2u). ∂u/∂x=u^2. (1/v). (2x) + (lnv). ( 2u). (2y)=u^2. (1/v). (2x) + (lnv). ( 2u). (2y)=(xy)^2. [ 1/(x^2+y^2) ].(2x) + [ln(x^2+y^2) ] .(2xy) (2y)=2x^3.y^2 /(x^2+y^2) + 4xy^2. ln(x^2+y^2)z=u^2.lnv∂z/∂y=u^2. (1/v).∂v/∂y + (lnv). ( 2u). ∂u/∂y=u^2. (1/v).(2y) + (lnv). ( 2u). (2x)=(xy)^2. [ 1/(x^2+y^2) ].(2y) + [ln(x^2+y^2) ] .(2xy) (2x)=2x^2.y^3 /(x^2+y^2) + 4x^2.yln(x^2+y^2)

答：马上为您查询

答：这是为您查询到的解析