x^4-1-4x^2-4x(分解因式)
4个回答
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x ⁴ -1 -4x²-4x
=x⁴-(4x²+4x+1)
=(x²)²-(2x+1)²
=[x²+(2x+1)][x²-(2x+1)]
=(x+1)²(x²-2x+1-2)
=(x+1)²[(x-1)²-2]
=(x+1)²(x-1+√2)(x-1-√2)
=x⁴-(4x²+4x+1)
=(x²)²-(2x+1)²
=[x²+(2x+1)][x²-(2x+1)]
=(x+1)²(x²-2x+1-2)
=(x+1)²[(x-1)²-2]
=(x+1)²(x-1+√2)(x-1-√2)
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展开全部
=(x^2+1)(x^2-1) - 4x^2-4x
=(x^2+1)(x^2-1) - 4x(x+1)
=(x^2+1)(x+1)(x-1) - 4x(x+1)
=(x+1)[(x^2+1)*(x+1)-4x]
=(x^2+1)(x^2-1) - 4x(x+1)
=(x^2+1)(x+1)(x-1) - 4x(x+1)
=(x+1)[(x^2+1)*(x+1)-4x]
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展开全部
x^4-(4x²+4x+1)
=x^4-(2x+1)²
=(x²+2x+1)(x²-2x-1)
=(x+1)²(x²-2x-1)
=x^4-(2x+1)²
=(x²+2x+1)(x²-2x-1)
=(x+1)²(x²-2x-1)
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