🌟+🌟+🌟+o=32 o+o+🌟+🌟+🌟+🌟=44 🌟=( ) O=()
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There are different approaches to solve this. One possible way is to use substitution.Let's say that the value of a star is "x" and the value of a circle is "y". Then we can set up the following equations:2x + y = 32 (from the first equation)4x + 2y = 44 (from the second equation)We can simplify the second equation by dividing both sides by 2:2x + y = 322x + y = 22Now we can subtract the first equation from the second to eliminate "y":2x + y - (2x + y) = 22 - 320 = -10This is a
咨询记录 · 回答于2023-03-29
+++o=32 o+o++++=44 =( ) O=( )
There are different approaches to solve this. One possible way is to use substitution.Let's say that the value of a star is "x" and the value of a circle is "y". Then we can set up the following equations:2x + y = 32 (from the first equation)4x + 2y = 44 (from the second equation)We can simplify the second equation by dividing both sides by 2:2x + y = 322x + y = 22Now we can subtract the first equation from the second to eliminate "y":2x + y - (2x + y) = 22 - 320 = -10This is a
解:⭐️为x，o为y，则3x+y=32，3y+4x＝44解：x＝10，y＝2，⭐️＝10，o＝2
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