Question

(5)1/((x-y)^2)+2/(x^2-3xy+2y^2)

Answer 1

问：(5)1/((x-y)^2)+2/(x^2-3xy+2y^2)

答：我们可以把分式化简为公共分母形式，即：1/((x-y)^2)+2/(x^2-3xy+2y^2) = [1*(x^2-3xy+2y^2) + 2*(x-y)^2]/[(x-y)^2 * (x^2-3xy+2y^2)]= (x^2-xy-y^2)/(x-y)^2 * (x-2y)/(x-y)*(x-y/2)/(x-2y)因此，原分式的化简结果为：(x^2-xy-y^2)/(x-y)^2 * (x-2y)/(x-y)*(x-y/2)/(x-2y)。