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3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)怎么算
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3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)=(3+1)x²+(3-2)x³=4x²-x³
咨询记录 · 回答于2022-07-30
3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)怎么算
3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)怎么算?我正在为您解答:
您好!根据目前的题目信息来看,3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)怎么算?先合并同类项
3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)=(3+1)x²+(3-2)x³=4x²-x³
3ⅹ²-(-3x³)+(-2x³)-(-ⅹ²)=(3+1)x²+(3-2)x³=4x²-x³=x²(4-x)