设f(z)=u(x,y)+iv(x,y)解析,且
1个回答
关注
展开全部
因为f(z)为解析函数,所以u(x,y),v(x+y)满足柯西黎曼方程ðu/ðx=ðv/ðy,ðu/ðy=-ðv/ðx。把u(x,y)=y代入,得ðu/ðx=0,ðv/ðx=-1,所以f'(z)=ðu/ðx+iðv/ðx=-i
咨询记录 · 回答于2021-11-20
设f(z)=u(x,y)+iv(x,y)解析,且
因为f(z)为旦饥解析函数,所以u(x,y),v(x+y)满足柯西黎曼方程ðu/ðx=ð和樱v/ðy,ðu/ðy=-ðv/ð唤迟丛x。把u(x,y)=y代入,得ðu/ðx=0,ðv/ðx=-1,所以f'(z)=ðu/ðx+iðv/ðx=-i
f(z)=u(x,y)+iv(x,y)解析,且ux+vx=0,求f(z)的表达式