Question

设f(z)＝u(x,y)+iv(x,y)解析，且

Answer 1

问：设f(z)＝u(x,y)+iv(x,y)解析，且

答：因为f(z)为解析函数，所以u(x,y),v(x+y)满足柯西黎曼方程ðu/ðx=ðv/ðy,ðu/ðy=-ðv/ðx。把u(x,y)=y代入，得ðu/ðx=0，ðv/ðx=-1，所以f'(z)=ðu/ðx+iðv/ðx=-i

答：f(z)=u(x,y)+iv(x,y)解析,且ux+vx=0,求f(z)的表达式