请问网上老师用6个不同数字,每组分3组,可组成多少组组完?如这6个数字分别为31,2,22,24,19,8
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这道题目可以使用排列组合的方法求解。从6个数字中选取3个数字,可以得到的不同组合数为:C(6,3) = 6! / (3! * (6-3)!) = 20对于每组选出的3个数字,它们之间可以有3!种不同的排列方式。因此,最终可以组成的不同组合数为:20 * 3! = 120也就是说,使用这6个数字能够组成120组完全不同的组合。
咨询记录 · 回答于2023-05-10
请问网上老师用6个不同数字,每组分3组,可组成多少组组完?如这6个数字分别为31,2,22,24,19,8
这道题目可以使用排列组合的方法求解。从6个数字中选取3个数字,可以得到的不同组合数为:C(6,3) = 6! / (3! * (6-3)!) = 20对于每组选出的3个数字,它们之间可以有3!种不同的排列方式。因此,最终可以组成的不同组合数为:20 * 3! = 120也就是说,使用这6个数字能够组成120组完全不同的组合。
请老师按照我给的数字组合给我看看吗
谢谢老师的指导
针对你给出的6个数字:31,2,22,24,19,8,它们的所有完整组合如下:[31, 2, 22] [31, 2, 24] [31, 2, 19] [31, 2, 8][31, 22, 2] [31, 22, 24] [31, 22, 19] [31, 22, 8][31, 24, 2] [31, 24, 22] [31, 24, 19] [31, 24, 8][31, 19, 2] [31, 19, 22] [31, 19, 24] [31, 19, 8][31, 8, 2] [31, 8, 22] [31, 8, 24] [31, 8, 19][2, 31, 22] [2, 31, 24] [2, 31, 19] [2, 31, 8][2, 22, 31] [2, 22, 24] [2, 22, 19] [2, 22, 8][2, 24, 31] [2, 24, 22] [2, 24, 19] [2, 24, 8][2, 19, 31] [2, 19, 22] [2, 19, 24] [2, 19, 8][2, 8, 31] [2, 8, 22] [2, 8, 24] [2, 8, 19][22, 31, 2] [22, 31, 24] [22, 31, 19] [22, 31, 8][22, 2, 31] [22, 2, 24] [22, 2, 19] [22, 2, 8][22, 24, 31] [22, 24, 2] [22, 24, 19] [22, 24, 8][22, 19, 31] [22, 19, 2] [22, 19, 24] [22, 19, 8][22, 8, 31] [22, 8, 2] [22, 8, 24] [22, 8, 19][24, 31, 2] [24, 31, 22] [24, 31, 19] [24, 31, 8][24, 2, 31] [24, 2, 22] [24, 2, 19] [24, 2, 8][24, 22, 31] [24, 22, 2] [24, 22, 19] [24, 22, 8]
[24, 19, 31] [24, 19, 2] [24, 19, 22] [24, 19, 8][24, 8, 31] [24, 8, 2] [24, 8, 22] [24, 8, 19][19, 31, 2] [19, 31, 22] [19, 31, 24] [19, 31, 8] [19, 2, 31] [19, 2, 22] [19, 2, 24] [19, 2, 8] [19, 22, 31] [19, 22, 2] [19, 22, 24] [19, 22, 8] [19, 24, 31] [19, 24, 2] [19, 24, 22] [19, 24, 8] [19, 8, 31] [19, 8, 2] [19, 8, 22] [19, 8, 24] [8, 31, 2] [8, 31, 22] [8, 31, 24] [8, 31, 19] [8, 2, 31] [8, 2, 22] [8, 2, 24] [8, 2, 19] [8, 22, 31] [8, 22, 2] [8, 22, 24] [8, 22, 19] [8, 24, 31] [8, 24, 2] [8, 24, 22] [8, 24, 19] [8, 19, 31] [8, 19, 2] [8, 19, 22] [8, 19, 24]