Question

已知ab满足b=a二分之根号a^2-4加根号4+-a^2+4求a-+2b加根号ab的值怎么做

Answer 1

问：已知ab满足b=a二分之根号a^2-4加根号4+-a^2+4求a-+2b加根号ab的值怎么做

答：亲，您好，很高兴为您解答。已知ab满足b=a二分之根号a^2-4加根号4+-a^2+4求a-+2b加根号ab的值答：b=√(a^2-4) /(a-2) +√(4-a^2)+4等式有意义,则有：a^2-4>=04-a^2>=0a-2≠0所以：a^2=4并且a≠2解得：a=-2代入原式有：b=0+0+4=4所以：|a-2b|+√(ab)ab=-8,二次根式无意义