求:2009嘉兴中考数学最后一题答案
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24.(1)在三角形ABC中 因为AC=,AB=x,BC=3-x.
所以1+x大于3-x 1+3-x大于x 解得1小于x小于2
(2)x=5/3或x=4/3
(3)面积最大为二分之根号二
很抱歉 有些符号打不出 答案估计返校日老师会给的
所以1+x大于3-x 1+3-x大于x 解得1小于x小于2
(2)x=5/3或x=4/3
(3)面积最大为二分之根号二
很抱歉 有些符号打不出 答案估计返校日老师会给的
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第一题,大于1小于2,第2题,三分之5,三分之4,第3题2分之根号2。这是标准答案!
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(1)在△ABC中,∵1=AC,xAB=,xBC−=3.
∴>−+−>+xxxx3131,解得21<<x. ······················································································ 4分 (2)①若AC为斜边,则22)3(1xx−+=,即0432=+−xx,无解. ②若AB为斜边,则1)3(22+−=xx,解得35=x,满足21<<x. ③若BC为斜边,则221)3(xx+=−,解得34=x,满足21<<x. ∴35=x或34=x. ·············································································································· 9分 3)在△ABC中,作ABCD⊥于D, 设hCD=,△ABC的面积为S,则xhS21=. ①若点D在线段AB上, 则xhxh=−−+−222)3(1. ∴22222112)3(hhxxhx−+−−=−−,即4312−=−xhx. ∴16249)1(222+−=−xxhx,即16248222−+−=xxhx. ∴462412222−+−==xxhxS21)23(22+−−=x(423x<≤). ································ 11分 当23=x时(满足423x<≤),2S取最大值21,从而S取最大值22. ························ 13分 ②若点D在线段MA上, 则xhhx=−−−−2221)3(. 同理可得,462412222−+−==xxhxS 21)23(22+−−=x(413x<≤), 易知此时22<S. 综合①②得,△ABC的最大面积为22. ·········································································· 14分
有些符号打不出
∴>−+−>+xxxx3131,解得21<<x. ······················································································ 4分 (2)①若AC为斜边,则22)3(1xx−+=,即0432=+−xx,无解. ②若AB为斜边,则1)3(22+−=xx,解得35=x,满足21<<x. ③若BC为斜边,则221)3(xx+=−,解得34=x,满足21<<x. ∴35=x或34=x. ·············································································································· 9分 3)在△ABC中,作ABCD⊥于D, 设hCD=,△ABC的面积为S,则xhS21=. ①若点D在线段AB上, 则xhxh=−−+−222)3(1. ∴22222112)3(hhxxhx−+−−=−−,即4312−=−xhx. ∴16249)1(222+−=−xxhx,即16248222−+−=xxhx. ∴462412222−+−==xxhxS21)23(22+−−=x(423x<≤). ································ 11分 当23=x时(满足423x<≤),2S取最大值21,从而S取最大值22. ························ 13分 ②若点D在线段MA上, 则xhhx=−−−−2221)3(. 同理可得,462412222−+−==xxhxS 21)23(22+−−=x(413x<≤), 易知此时22<S. 综合①②得,△ABC的最大面积为22. ·········································································· 14分
有些符号打不出
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2009-06-18
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海伦公式最简单!
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