Question

(-3x²y的-2次方)的-3次方*(-2x的-3次方y的4次方)的-2次方

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Answer 1

(-3x^2y^-2)^-3*(-2x^-3*y^4)^-2=(-3)^-3*x^[2*(-3)]*y^[(-2)*(-3)]*(-2)^(-2)*x^[(-3)*(-2)]*y^[4*(-2)]=(-1/27)*x^(-6)*y^6*(1/4)*x^6*y^(-8)=(-1/27)*(1/4)*x^(-6+6)*y^(6-8)=(-1/108)*x^0*y^(-2)=-1/108y^2