Question

因式分解：x^2（y^2-1）+（1-y^2）

^2表示二次方
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Answer 1

x^2(y^2-1)+(1-y^2)
解：原式=x^2(y-1)(y+1)+(1-y)(1+y)
=x^2(y-1)(y+1)-(y-1)(y+1)
=(x^2-1)(y+1)(y-1)
=(x+1)(x-1)(y+1)(y-1)

Answer 2

原式=x^2(y^2-1)-(y^2-1)
=(y^2-1)(x^2-1)
=(y+1)(y-1)(x+1)(x-1)