因式分解1~4
1个回答
展开全部
4x²-4x-y²+4y-3
=4x²-4x+1-y²+4y-4
=(2x-1)²-(y-2)²
=(2x-1-y+2)(2x-1+y-2)
=(2x-y+1)(2x+y-3)
(x+y-2xy)(x+y-2)+(xy-1)²
=(x+y)²-(2xy+2)(x+y)+4xy+x²y²-2xy+1
=(x+y)²-2(xy+1)(x+y)+(xy+1)²
=(x+y-xy-1)²
a^4+4
=a^4+4a²+4-4a²
=(a²+2)-4a²
=(a²-2a+2)(a²+2a+2)
x³+5x²+3x-9
=x³+5x²-6x+6x+3x-9
=x(x²+5x-6)+9x-9
=x(x-1)(x+6)+9(x-1)
=(x-1)(x²+6x+9)
=(x-1)(x+3)²
你没有悬赏,真不想帮你做
=4x²-4x+1-y²+4y-4
=(2x-1)²-(y-2)²
=(2x-1-y+2)(2x-1+y-2)
=(2x-y+1)(2x+y-3)
(x+y-2xy)(x+y-2)+(xy-1)²
=(x+y)²-(2xy+2)(x+y)+4xy+x²y²-2xy+1
=(x+y)²-2(xy+1)(x+y)+(xy+1)²
=(x+y-xy-1)²
a^4+4
=a^4+4a²+4-4a²
=(a²+2)-4a²
=(a²-2a+2)(a²+2a+2)
x³+5x²+3x-9
=x³+5x²-6x+6x+3x-9
=x(x²+5x-6)+9x-9
=x(x-1)(x+6)+9(x-1)
=(x-1)(x²+6x+9)
=(x-1)(x+3)²
你没有悬赏,真不想帮你做
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询