
求学霸指点一下,谢谢
1个回答
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猜分解因式:
(1)原式=(x-2+5)^2=(x+3)^2.
(2)原式=(a+b-3)^2.
(3)原式=(z^2+1-2z)^2=(z-1)^4.
(4)原式=(x+y)[(x+y)^2-4xy]
=(x+y)(x^2-2xy+y^2)
=(x+y)(x-y)^2.
(1)原式=(x-2+5)^2=(x+3)^2.
(2)原式=(a+b-3)^2.
(3)原式=(z^2+1-2z)^2=(z-1)^4.
(4)原式=(x+y)[(x+y)^2-4xy]
=(x+y)(x^2-2xy+y^2)
=(x+y)(x-y)^2.
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