Question

C语言问题求大神指教

#include <stdio.h>
#include <stdlib.h>
#define abc(c) if(c>'Z') c='A'+(c-'Z')-1; if(c<'A') c='Z'-('A'-c)+1;

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
int s,t,A,B,C=303;
float i=1;
double x;
while(i<=6)
{x=7*303/((5.6)-(i));
t=x;
i+=1;
printf("%f\n",x);
if(t-x==0||x>0)
{s=t;
break;}
}
A=s/5;
B=s-A-C;
printf("sum=%d\n",s);
printf("A=%d\n",A);
printf("B=%d\n",B);
printf("C=%d\n",C);
return 0;
}
输出的s等于0，也就是if(t-x==0||x>0)的条件每一组x和t都不满足，但是在我输出的x和t中确实又满足条件的一组，为什么？

Answer 1

#include <stdio.h>
#include <stdlib.h>
#define abc(c) (if(c>'Z') c='A'+(c-'Z')-1;  if(c<'A') c='Z'-('A'-c)+1;)

/* run this program using the console pauser or add your own getch, system("pause") or input loop */

int main(int argc, char *argv[]) {
	double A,B,C=303;
	float i=1;
	double s,t,x;
	while(i<=6)
	{
		x=7*303/((5.6)-(i));
		t=x;
		i+=1;
		printf("%lf\n",x);
		if(( t-x>-0.0000001 && t-x< 0.000001 )||x>0)
		{
			s=t;printf("%lf\n",s);
			break;
		}
	}
	A=s/5;
	B=s-A-C;
	printf("sum=%lf\n",s);
	printf("A=%lf\n",A);
	printf("B=%lf\n",B);
	printf("C=%lf\n",C);
	return 0;
}