Question

Java，定义一个数组a1，其中包含15个元素，在定义一个数组a2，给他们分配10个元素的空间

Answer 1

String[] a1 = {"1","2","3","4","5","6","7","8","9","10","11","12","13","14","15"};
String [] a2 = new String[10];
try{

for(int i=2;i<15;i++){
a2[i-2]=a1[i];
}
}catch(ArrayIndexOutOfBoundsException e){
}
System.out.println("a1数组里的内容："+Arrays.toString(a1));
System.out.println("a2数组里的内容："+Arrays.toString(a2));

Answer 2

public static void main(String[] args) {
// TODO Auto-generated method stub
int a1[]={2,12,23,11,7,1,5,8,9,14,25,43,0,17,99};
int a2[]=new int[10];
try{
for(int i=2;i<14;i++)
a2[i-2]=a1[i];}catch (ArrayIndexOutOfBoundsException e){
System.out.println("数组下标越界！");
}
System.out.print("a1=");
for(int i=0;i<a1.length;i++)
System.out.print(a1[i]+" ");
System.out.println();
System.out.print("a2=");
for(int i=0;i<a2.length;i++)
System.out.print(a2[i]+" ");
System.out.println();
}

Answer 3

int[] a1=new int[15];
int[] a2=new int[10];

Answer 4

你这是想问什么？

追问

图片的第二题