Question

数学大神，请不吝赐教。

Answer 1

B
i: x-direction
j: y-direction
k: z-direction

L :
(x+1)/5 = (y-3)/2 = (z+2)/1 = k
x=5k-1, y=2k+3, z= k-2

k=1, A(4, 5, -1) is on L
k=2, B(9, 7, 0) is on L

C(3,0,2)
CA =OA-OC =i+5j-3k
CB = OB-OA =6i+7j-2k

CA x CB3
=(i+5j-3k) x(6i+7j-2k)
=(7k+2j)+(-30k-10i)+(-18j+21i)
=11i-16j-23k

C(3,0,2)
平面方程
11(x-3)-16(y-0) -23(z-2) =0