Question

计算题，求答案

Answer 1

这样求助不好吧，问其中一道确实不会做的尚有情可原，你课上都干啥了，学习可不是投机取巧能做得来的，还是多看看书，补补课吧！

Answer 2

(1) ∫dx/(2x-3) = (1/2)ln|2x-3| + C
(2)
6x+1 = 3(2x-3) + 10
∫(6x+1)/(2x-3) dx
=∫[ 3+ 10/(2x-3)] dx
= 3x +5ln|2x-3| + C
(3)
∫dx/(x^2+2x-3)
=∫dx/[(x+3)(x-1)]
=(1/4) ∫ [1/(x-1) - 1/(x+3) ] dx
=(1/4)ln|(x-1)/(x+3)| + C
(4)
x^2+2x+3 = (x+1)^2 + 2
let
x+1 = √2tanu
dx = √2(secu)^2 du
∫dx/(x^2+2x+3)

=∫√2(secu)^2 du/[2(secu)^2]
=(√2/2) ∫ du
=(√2/2) u + C
=(√2/2)arctan[(x+1)/√2] + C