
负3分之17兀的正切,正弦,余弦
1个回答
展开全部
sin(-17π/3)=sin(-6π+π/3)=sin(π/3)=(√3)/2(sin是周期函数,sin(x+2kπ)=sin(x))
cos(-17π/3)=cos(-6π+π/3)=cos(π/3)=1/2(cos也是周期函数,cos(x+2kπ)=cos(x))
tan(-17π/3)=sin(-17π/3)/cos(-17π/3)=√3
cos(-17π/3)=cos(-6π+π/3)=cos(π/3)=1/2(cos也是周期函数,cos(x+2kπ)=cos(x))
tan(-17π/3)=sin(-17π/3)/cos(-17π/3)=√3
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询