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a) sin^-1 x stands for the inverse of sin x, while (sinx)^-1 stands for the reciprocal of sinx.
b) sin^-1 x = arcsinx, and (sinx)^-1 = cscx
c) sin^-1 (1/2) = pi/6, because the range of inverse sine is [-pi/2, pi/2]
a) Let x = tan^-1 (3/7). Then, tanx = 3/7, sinx = 3/√(3^2+7^2)
b) Let a = cos^-1(x^2-1) ==> cos a = (x^2-1), sin a = √[1-(x^2-1)^2]
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