Question

数学问题:分解因式

5(x+y)(a-b+c)+3(x-y)(b-a-c)

Answer 1

思路：先乘起来 合并同类项以后再分解因式
原式=(5ax-5bx+5cx+5ay-5by+5cy)+(3bx-3ax-3cx+3by-3ay-3cy)
=2ax-2bx+2cx+2ay-2by+2cy
=2x(a-b+c)+2y(a-b+c)
=2(x+y)(a-b+c)

Answer 2

(a-b+c)(5x+5y-3x+3y)=(a-b+c)(2x+8y)

Answer 3

原式=5(x+y)(a-b+c)-3(x-y)(a-b+c)
=(5x+5y-3x+3y)(a-b+c)
=(2x+8y)(a-b+c)
=2(x+4y)(a-b+c)

Answer 4

2xa+8ya-2xb-8yb+2xc+8yc

Answer 5

(3x)^1-4=(3x+2)(3x-2)
16x^2-11=(4x+√11)(4x-√11)
只能这样了！
x^4-36=(x^2+6)(x^2-6)
如果想再进一步的话就是
=(x^2+6)(x+√6)(x-√6)
x^4-225
=(x^2+15)(x^2-15) 如果想再进一步的话就是
同上

Answer 6

4a平方+4分之1-2a-9b平方=(2a-1/2)平方-9b平方=(2a+3b-1/2)x(2a-3b-1/2)