Question

数学题：xy = e(x+y).求dy.在线等.？

Answer 1

[y-e^(x+y)]*dx /[e^(x+y) -x],5,xy=e(x+y)
xy=ex+ey
(x-e)y=ex
y=ex/x-e
dy=d(ex/x-e),2,整理得：y=ex/(x-e)
dy=[ex*x-x*(x-e)]/(x-e)(x-e) *dx
dy=(ex*x-x*x+xe)x-e)(x-e) *dx,2,两边同取导数
dy/dx=(e-y)/(x-e)
y=e*x/(x-e)
dy=-e方/（x-e)方*dx,2,xy=ex*ey
x/ex=ey/y
两边求导,1,数学题：xy = e(x+y).求dy.在线等.
谢谢。不好意思，是xy = e的（x+y）次方。没有表达清楚，抱歉。