Question

求(sin6+cos15sin9)\cos6-sin15cos9的值

答案是2-根三 要过程，谢谢

Answer 1

原式=[cos15sin9+sin(15-9)]/[sin15sin9-cos(15-9)]
=(cos15sin9+sin15cos9-cos15sin9)/(sin15sin9-cos15cos9-sin15sin9)
=sin15cos9/(-cos15cos9)
=sin15/cos15
=-tan15
=-tan(45-30)
=-(tan45-tan30)/(1+tan45tan30)
=-2+√3