Question

怎样判断一个服务器上是否有webservice c#实现

在客户端写一个程序来判断指定的ip是否有webservice，之前想用httprequest请求一个确定的asmx文件，不知道能不能用其他的办法解决。
一楼的代码不好读啊，拿着msdn搜读不懂，有些类是你自己写的吧！
不过还得谢谢你！

再次说明一下，我的问题是局域网有机器若干，我采用for循环在一个网段内扫描，将包含webservice的机器ip收集下来，存到本地。

Answer 1

以下代码演示了根据给定注册中心使用的WSDL规范实例来查找一个机构。

String schemeName = "uddi-org:types";

ClassificationScheme uddiOrgTypes = bqm.findClassificationSchemeByName(null, schemeName);

/*

* Create a classification, specifying the scheme
* and the taxonomy name and value defined for WSDL
* documents by the UDDI specification.

*/

Classification wsdlSpecClassification = blcm.createClassification(uddiOrgTypes, "wsdlSpec", "wsdlSpec");

ArrayList classifications = new ArrayList(); classifications.add(wsdlSpecClassification);

// Find concepts

BulkResponse br = bqm.findConcepts(null, null, classifications, null, null);

接着，你必须遍历concept，找到它们对应的WSDL文件，并显示出使用每个文件的机构：

// Display information about the concepts found

Collection specConcepts = br.getCollection();

Iterator iter = specConcepts.iterator();

if (!iter.hasNext()) {

System.out.println("No WSDL specification concepts found");

} else {

while (iter.hasNext()) {

try{

Concept concept = (Concept) iter.next();
String name = getName(concept);
Collection links = concept.getExternalLinks();
System.out.println("\nSpecification Concept:\n Name: " +name + "\n Key: " + concept.getKey().getId() + "\n Description: " + getDescription(concept));
if (links.size() > 0) {

ExternalLink link =
(ExternalLink) links.iterator().next();
System.out.println("URL of WSDL document: '" link.getExternalURI() + "'");

}

// Find organizations that use this concept

ArrayList specConcepts1 = new ArrayList();

specConcepts1.add(concept);

br = bqm.findOrganizations(null, null, null, specConcepts1, null, null);

Collection orgs = br.getCollection();

// Display information about organizations

... }

查找服务和服务绑定
以下代码演示了getService()和getServiceBindings()方法的使用：

Iterator orgIter = orgs.iterator();

while (orgIter.hasNext()) {

Organization org = (Organization) orgIter.next();

Collection services = org.getServices();

Iterator svcIter = services.iterator();

while (svcIter.hasNext()) {

Service svc = (Service) svcIter.next();

Collection serviceBindings = svc.getServiceBindings();

Iterator sbIter = serviceBindings.iterator();

while (sbIter.hasNext()) {

ServiceBinding sb =

(ServiceBinding) sbIter.next();

}

}

}