Question

这两道计算怎么算啊，求有过程

帮个忙啊，谢谢

Answer 1

（1）解：
原式=(x-5)/(x+4)(x-4)-[-3/(x-4)]
=(x-5)/(x+4)(x-4)-[-3(x+4)/(x+4)(x-4)]
=[(x-5)+3(x+4)]/(x+4)(x-4)
=(4x+7)/(x^2-16)
（2）解：
原式=3(x-1)/x(x-1)-[-6x/x(x-1)]-(x+5)/x(x-1)
=3(x-1)/x(x-1)+6x/x(x-1)-(x+5)/x(x-1)
=[3(x-1)+6x-(x+5)]/x(x-1)
=8(x-1)/x(x-1)
=8/x