Question

2句实现.设计一个程序，将从键盘上输入的百分制成绩转换成对应的五分制成绩并输出。

2句实现.设计一个程序，将从键盘上输入的百分制成绩转换成对应的五分制成绩并输出。90分以上为A,80-89分为B,70-79分为C，60-69分为D，60分一下为E。用开关语。

Answer 1

#include<stdio.h>

int main(void)
{
float score;
char grade;

do
{
printf("please input the score(0-100):");
scanf("%f", &score);
} while (score > 100 || score < 0);

switch ((int)score / 10)
{
case 10:
case 9:
grade = 'A';
break;
case 8:
grade = 'B';
break;
case 7:
grade = 'C';
break;
case 6:
grade = 'D';
break;
default:
grade = 'E';

}
printf("score=%.1f,grade=%c\n", score, grade);

return 0;

}

Answer 2

两句？
String[] aaa = new String[]{"t","t","t","t","E","D","C","B","A"}
System.out.print(aaa[分数/10]);
java的代码。其他语言你自己改，很简单的。

Answer 3

import java.util.*;
/**
 * @author hardneedl
 */
public class ScoreDemo {

    private interface Convertor<S,R>{
        R convert(S s);
    }

    private enum ScoreLevel {
        A(90,100),
        B(80,89),
        C(70,79),
        D(60,69),
        E(0,59)
        ;
        private int low,hi;

        ScoreLevel(int low, int hi) {
            this.hi = hi;
            this.low=low;
        }

        public String toString() {
            return name();
        }
    }

    static private class ScoreLevelConvertor implements Convertor<Integer, ScoreLevel>{
        public ScoreLevel convert(Integer s) {
            for(ScoreLevel sl:ScoreLevel.values()) {
                if (s>=sl.low&&s<=sl.hi)
                    return sl;
            }
            return null;
        }
    }

    public static void main(String... args) {
        Scanner scanner = new Scanner(System.in);

        int i = -9;
        while (i < 0 || i > 100) {
            System.out.printf("输入分数(大于等于0且小于等于100)");
            i = scanner.nextInt();
        }

        Convertor<Integer,ScoreLevel> c = new ScoreLevelConvertor();
        System.out.println(c.convert(i));
    }
}

Answer 4

Switch，Case语句