Question

求解此道理论力学题目（不要用达朗贝尔原理没学过）

Answer 1

板的运动微分方程                                                  ac*m=F-f1                         (1)

滚子质心平动的运动微分方程                                ao*(m/2)=f1-f2                  (2)

滚子绕质心转动运动微分方程 （动量矩定理）      JOε=r(f1+f2)                     (3)

补充方程                                                                 ao=εr                                (4)

                                                                               ac=ao+εr=2ao=2εr           (5)

以上,五个方程联立解

滚子角加速度             ε=F/3mr

板的加速度                ac=2εr=2F/3m