Question

第9题，急求！拜托了！！

Answer 1

9
(1)
原式
=(1/5)[lg32+log4 4的平方+6lg2的-1次方]+(1/5)lg5的-1次方
=(1/5)[lg32+2log4 4+lg2的-6次方]-(1/5)lg5
=(1/5)[lg2的5次方+2*1+lg2的-6次方]-(1/5)lg5
=(1/5)[2+lg（2的5次方*2的-6次方）]-(1/5)lg5
=(1/5)[2+lg（2的-1次方）]-(1/5)lg5
=2/5-（1/5）lg2-(1/5)lg5
=2/5-(1/5)lg(2*5)
=2/5-(1/5)lg10
=2/5-1/5
=1/5
(2)

原式=lg2*(lg2+lg50)+lg25
=lg2*lg(2*50)+lg25
=lg2*lg100+lg25
=lg2*lg10的平方+lg25
=lg2*(2lg10)+lg25
=2lg2+lg25
=lg2的平方+lg25
=lg(4*25)
=lg100
=lg10的平方
=2lg10
=2*1
=2