已知a+a分之1=7，求根号a+根号a分之1的值
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log6^根号24
=lg根号24/lg6
=1/2*lg24/lg6
=lg24/(2lg6)
=(lg4+lg6)/(2lg6)
=lg4/(2lg6)+1/2
=2lg2/[2(lg2+lg3)]+1/2
=lg2/(lg2+lg3)+1/2
=(lg2/lg3)/(lg2/lg3+1)+1/2
=log3^2/(log3^2+1)+1/2
=a/(a+1)+1/2
=2a/(2a+2)+(a+1)/(2a+2)
=(3a+1)/(2a+2)
=lg根号24/lg6
=1/2*lg24/lg6
=lg24/(2lg6)
=(lg4+lg6)/(2lg6)
=lg4/(2lg6)+1/2
=2lg2/[2(lg2+lg3)]+1/2
=lg2/(lg2+lg3)+1/2
=(lg2/lg3)/(lg2/lg3+1)+1/2
=log3^2/(log3^2+1)+1/2
=a/(a+1)+1/2
=2a/(2a+2)+(a+1)/(2a+2)
=(3a+1)/(2a+2)
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