Question

8.如图，CD⊥AB，BE⊥AC，垂足分别为D，E，BE交CD于点F，且AD=DF，求证:AC=B

8.如图，CD⊥AB，BE⊥AC，垂足分别为D，E，BE交CD于点F，且AD=DF，求证:AC=BF

Answer 1

 

Answer 2

∵CD⊥AB，BE⊥AC
∴∠CEF=∠BDF=∠ADC=90°
∵∠CFE=∠BFD
∴∠C=∠B
∵AD=DF,∠ADC=∠BDF
∴⊿ADC≌⊿BDF﹙AAS﹚
∴AC=BF

Answer 3

没有