Question

正则表达式间隔符空格如何用逗号代替

例如用 ^(\S+) (\S+) (\S+)
\[([\w:/]+\s[+\-]\d{4})\] "(.+?)" (\d{3}) (\S+)(?=
"([^"]+)" "([^"]+)")?匹配字符串
548a847502112025,2014/12/12 15:51:52,15.1.3.140,57665,15.1.3.185,7180,unknown,POST,"",http://15.1.3.185:7180/cmf/charts/timeSeries

Answer 1

var reg = /\s+([^\s]*)/g;

var str = '548a847502112025 2014/12/12 15:51:52 15.1.3.140 57665 15.1.3.185 7180 unknown POST "" hxtsdftp:/s/15.1.3.185:s718f0/cmf/charts/timeSeries';


str.replace(reg, ",$1");
// 回答完毕，采纳即可

追问

我开始写的正则表达式有错误，我的目的是字符串548a847502112025,2014/12/12 15:51:52,15.1.3.140,57665,15.1.3.185,7180,unknown,POST,"",http://15.1.3.185:7180/cmf/charts/timeSeries以逗号间隔为基准分开输出，分成十个字符串。而且“”不显示。非常感谢！！！

追答

var str = '548a847502112025,2014/12/12 15:51:52,15.1.3.140,57665,15.1.3.185,7180,unknown,POST,"",htsdfsdftp:/sf/15.1.3.185:7180/cmf/charts/timeSeries';

var arr = str.replace(/\,\"\"/g,"").split(",");
for(var i = 0;i<arr.length;i++){
    console.log(arr[i]);
}

回答完毕，采纳即可