Question

帮我做一个Java的一个小程序

Typically, books are identified by an International Standard Book Number (ISBN) which adheres to a specific format, e.g. 0-393-30375-A.

Write a program that generates a random ISBN that follows the following rules:

a. The first digit indicates whether the language in which the book is written is English; this is must be a zero or one.

b. The next group of three digits specifies the publisher and must not contain an 8 or a 9

c. The group after that is a number assigned by the publisher to identify the book. The publisher is prompted to enter a value between 10000 and 99999 (it is not randomly generated). No validation needs to be preformed.

d. The ISBN ends with a random uppercase character (A-Z), called a check character.

Then display the ISBN number in the following format:
a-bbb-ccccc-d.

Your programs output should look like this:

ISBN is 0-123-45678-X

Language = 0
Publisher = 123
Book = 45678
Check = X

Answer 1

public class Test {
public static void main(String[] args) {
Random random = new Random();
int a = random.nextInt(2);
int b = random.nextInt(8);
int c = random.nextInt(8);
int d = random.nextInt(8);
int e = random.nextInt(90000) + 10000;
char f = (char) (random.nextInt(26) + 'A');

System.out.printf("ISBN is: %d-%d%d%d-%d-%c\n", a, b, c, d, e, f);
System.out.printf("Language = %d\n", a);
System.out.printf("Publisher = %d%d%d\n", b, c, d);
System.out.printf("Book = %d\n", e);
System.out.printf("Check = %c", f);
}

}